This week in AP-Calculus, we learned about solids of revolution. We also took the 7.1-7.2 quiz, and I did pretty good on it. Solids of revolution using the disk method has been pretty easy so far. The concept took some explaining since it involved picturing a three dimensional shape, only using its two dimensional profile. Once I wrapped my head around that, the process was fairly quick. The equation for finding the volume of the shape just uses the equation for the volume of a cylinder, but replaces some parts of the equation with parts of integrals. The equation is pretty basic and can be used for the majority of the problems, even those in terms of y. Basically, the volume is equal to pi times the integral of the function, but you square the entire function. You use the bounds like normal and it will output the volume of the 3D shape created by the function.
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February 2018
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